Ask Question
9 February, 14:05

A small submarine starts at - 1,260 feet in relation to sea level. Then it descends 5 feet per minute for 12 minutes. What is the new position of the submarine in relation to sea level? - 1,260 + (-5) (12) = - 1,260 + 60 = - 1,200

+4
Answers (2)
  1. 9 February, 14:10
    0
    That would be - 1260 + 12 (-5) = - 1260 - 60 = - 1320 feet
  2. 9 February, 14:16
    0
    The submarine is at - 1260 ft.

    It descends 5 ft/min for 12 min.

    12 min * 5 ft/min = 60 ft.

    It descended 60 ft, so you must subtract 60 ft from - 1260 ft.

    -1260 ft + (-5) (12) ft = - 1260 ft - 60 ft = - 1320 ft

    The error in the last line in the problem is that (-5) (12) = - 60, not 60.

    The correct line is:

    -1260 + (-5) (12) = - 1260 - 60 = - 1320
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A small submarine starts at - 1,260 feet in relation to sea level. Then it descends 5 feet per minute for 12 minutes. What is the new ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers