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30 March, 03:11

Derivative of sin11xcos11x

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  1. 30 March, 03:24
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    Hello here is a solution:

    f' (x) = (sin11x) 'cos11x + sin11x (cos11x) '

    (sin (ax+b)) '=a cos (ax+b)

    (cos (ax+b)) '=-a sin (ax+b)

    f' (x) = 11 cos11xcos11x-11sin11xsin11x

    f' (x) = 11 (cos11x) ²-11 (sin11x) ²
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