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2 January, 18:43

A rectangle has a perimeter of 72 feet. The length is twice the width. Find the dimensions of the rectangle ...

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  1. 2 January, 18:49
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    Set up a system of equations:

    2l + 2w = 72

    l = 2w

    Solve the system using substitution:

    2 (2w) + 2w = 72

    Solve for w:

    4w + 2w = 72

    -> 6w = 72

    -> w = 12

    Plug in the value for 'w' in the second equation:

    l = 2 (12)

    -> l = 24

    The width is 12.

    The length is 24.
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