The product of two consecutive integers is 72. The equation x (x + 1) = 72 represents the situation, where

represents the smaller integer. Which equation can be factored and solved for the smaller integer?

1 x2 + x-72=0

x2+x+72 = 0

2 + 2x - 72 = 0

2 + 2x + 72=0

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Question

Guest

Mathematics

26 March, 20:23

The product of two consecutive integers is 72. The equation x (x + 1) = 72 represents the situation, where

represents the smaller integer. Which equation can be factored and solved for the smaller integer?

1 x2 + x-72=0

x2+x+72 = 0

2 + 2x - 72 = 0

2 + 2x + 72=0

-

Intro

+1

Answers (1)

Know the Answer?

Trey Gibbs · Answer 1

x^2 + x-72=0

Step-by-step explanation:

x (x+1) = 72

Distribute

x^2 + x = 72

Subtract 72 from each side

x^2 + x - 72 = 0

Now this is the equation we can factor

The product of two consecutive integers is 72. The equation x (x + 1) = 72 represents the situation, whererepresents the smaller integer. Which equation can be factored and solved for the smaller integer?1 x2 + x-72=0x2+x+72 = 02 + 2x - 72 = 02 + 2x + 72=0-Intro

The product of two consecutive integers is 72. The equation x (x + 1) = 72 represents the situation, where

represents the smaller integer. Which equation can be factored and solved for the smaller integer?

1 x2 + x-72=0

x2+x+72 = 0

2 + 2x - 72 = 0

2 + 2x + 72=0

-

Intro