Solve the following system. y = x 2 - 9x + 10 and x + y + 5 = 0. Enter the solution with the smaller x value first.

The solutions are (__a0, __ a1) and (__a2, __ a3)

Solutions are (3, - 8) and (5, - 10)

Step-by-step explanation:

From the equation x + y + 5 = 0 : -

x = - y - 5

Substitute for x in the other equation:

y = (-y - 5) ^2 - 9 (-y-5) + 10

y = (y^2 + 10y + 25) + 9y + 45 + 10

y^2 + 18y + 80 = 0

(y + 8) (y + 10) = 0

y = - 8, - 10

Substitute these values of y in the equation x + y + 5 = 0:-

x = - 8:-

x - 8 + 5 = 0 so x = 8-5 giving. x = 3

x = - 10:-

x - 10 + 5 = 0 sox = 10-5 giving x = 5