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22 May, 21:53

Lisa is a 100 yards away from tim and lisa can run to tim in 18 seconds i have to show a table which values the distance between lisa and tim assuming rate never change and how long will it take lisa to reach tim in 12 sec

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  1. 22 May, 21:57
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    For this case we have the following equation:

    d = v * t

    Where,

    d: distance

    v: speed

    t: time

    the equation for lisa is:

    d = (100/18) * t

    The table is:

    1 5.555555556

    2 11.11111111

    3 16.66666667

    4 22.22222222

    5 27.77777778

    6 33.33333333

    7 38.88888889

    8 44.44444444

    9 50

    10 55.55555556

    11 61.11111111

    12 66.66666667

    13 72.22222222

    14 77.77777778

    15 83.33333333

    16 88.88888889

    17 94.44444444

    18 100

    For t = 12 we see in the table that the distance is 66.66.

    Therefore, to reach tim we have:

    d = 100-66.66

    d = 33.34

    Answer:

    it will take lisa 33.34 yd to reach tim in 12 sec
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