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A group of backpackers hiked 38 km over three days. the first day, they hiked 1 km less than 3 times as far as the second day. the third day, they hiked 2 km less than the first day. how far did they hike the first day

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  1. 1 May, 15:11
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    38 km = (3x-1) + x + ((3x-1) - 2)

    38 = 3x-1+x+3x-1-2

    38 = 7x-4

    7x=42

    x=6 km - - > second day

    Test: 38 = (3*6-1) + 6 (3*6-1) - 2)

    --> frist day: 3*6-1 = 17 km
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