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27 February, 19:46

Find the inverse of the logarithmic function y = log₂ (x + 7)

y = x2 - 7

y = x2 + 7

y = 2x2 + 7

y = 2x - 7

y = 2x + 7

+2
Answers (2)
  1. 27 February, 20:04
    0
    y=2x-7 answered off of a graphing calculator
  2. 27 February, 20:12
    0
    1. Interchange x and y: x = log₂ (y + 7)

    2. Solve this resulting equatino for y:

    x x

    2 = y + 7 = > y = 2 - 7

    3. Replace "y" with

    -1 - 1 x

    f (x) : f (x) = 2 - 7 This is the desired inverse.
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