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16 January, 20:19

Find the equation of a line through (4,-5) perpendicular to 6x-2y=7

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  1. 16 January, 20:47
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    Answer: y=-1/3+2/3

    Step-by-step explanation:

    1. 6x-2y=7 subtract 6x from both sides.

    2. - 2y=-6x+7 divide both sides by - 2 to isolate y

    3. y=3x+7 that's the y=Mx+b format, now we must find the negative inverse of the slope (m) which is - 1/3.

    4. Plug in variables.

    -5=-1/3 (4) + b

    5. Solve:

    -5=-4/3+b

    add 4/3 to both sides to get - 3 2/3=b

    6. Make y=mx+b equation.

    y=-1/3x+2/3
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