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9 December, 05:35

Given the function ƒ (x) = 3x + 5, find ƒ (4) and x such that ƒ (x) = 38.

A. 17; 11

B. 20; 13

C. 12; 15

D. 24; 9

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Answers (1)
  1. 9 December, 06:04
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    The answer is A, just plug 4 inside f (x) = 3 (4) + 5 = 17

    3x+5=38

    3x=33

    Divid by 3 both side

    X=11
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