On the second day of a hiking trip, the tourists covered 17% bigger distance than on the first day. By how many percent did their average speed change from first to second day, if on the second day they were hiking for 20% longer time?

Question

Devin Orozco

Mathematics

17 January, 06:47

On the second day of a hiking trip, the tourists covered 17% bigger distance than on the first day. By how many percent did their average speed change from first to second day, if on the second day they were hiking for 20% longer time?

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Answers (2)

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Jaxson Hodge · Answer 1

Speed=distance/time

suppose the distance of the first day is d, and the time is t

distance of the second day: d+0.17d=1.17d

time of the second day: t+0.2t=1.2t

speed of the second day: 1.17d/1.2t=0.975 (d/t) = (1-0.025) (d/t)

so the speed of the second day is 2.5% slower than the first day.

Bobby Sanford · Answer 2

Speed=distance/time suppose the distance of the first day is d, and the time is distance of the second day: d+0.17d=1.17dtime of the second day: t+0.2t=1.2tspeed of the second day: 1.17d/1.2t=0.975 (d/t) = (1-0.025) (d/t) so the speed of the second day is 2.5% slower than the first day.