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26 February, 04:14

Solve for x over the complex numbers. x2+10x+41=0

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Answers (2)
  1. 26 February, 04:25
    0
    The correct answer is X = - 5 ± 41
  2. 26 February, 04:38
    0
    X²+10x+41=0

    using x = (-b±√b²-4ac) ½

    where a = 1

    b=10

    c=41

    x = (-10±√10²-4*1*41) ½

    x=-5 ± √ (100-164)

    x=-5±√ (-64) ½

    x=-5±4i

    x=-5+4i or - 5-4i

    where i = √-1
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