Solve the following problem for the roots by using the quadratic formula. 2 (6 - x) = x (x + 5)

Solve for x:

2 (6 - x) = x (x + 5)

Expand out terms of the left hand side:

12 - 2 x = x (x + 5)

Expand out terms of the right hand side:

12 - 2 x = x^2 + 5 x

Subtract x^2 + 5 x from both sides:

-x^2 - 7 x + 12 = 0

Multiply both sides by - 1:

x^2 + 7 x - 12 = 0

x = (-7 ± sqrt (7^2 - 4 (-12))) / 2 = (-7 ± sqrt (49 + 48)) / 2 = (-7 ± sqrt (97)) / 2:

Answer: x = (-7 + sqrt (97)) / 2 or x = (-7 - sqrt (97)) / 2