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17 May, 15:04

Preform the indicated operation: (2x+1) ^2

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  1. 17 May, 15:21
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    (2x+1) ^2

    = (2x + 1) (2x + 1)

    = (2x) (2x) + (2x) (1) + (1) (2x) + (1) (1)

    = 4x^2 + 2x + 2x + 1

    = 4x^2 + 4x + 1
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