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7 August, 03:05

When 10x^3+mx^2 - x+10 is divided by 5x-3, the quotient is 2x^2+no-2 and the remainder is 4. What is the value of m and n?

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  1. 7 August, 03:24
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    Hello,

    10x^3+mx^2-x+10 = (5x-3) (2x^2+nx-2) + 4

    =10x^3-6x^2+5nx^2-3nx-10x+6+4

    ==>

    -3n-10=-1 = = >3n=-9==>n=-3

    -6+5n=m = = >-6-15=m==>m=-21
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