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Pennington
Mathematics
31 August, 21:45
F (x) = x3 + 4x2 + x - 6 real zeros
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Lara Novak
31 August, 22:13
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Hello,
f (x) = x^3+4x²+x-6
=x^3-x²+5x²-5+x-1
=x² (x-1) + 5 (x-1) (x+1) + x-1
= (x-1) (x²+5x+5+1)
= (x-1) (x²+2x+3x+6)
= (x-1) (x (x+2) + 3 (x+2))
= (x-1) (x+2) (x+3)
Zeros are 1,-2,-3.
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