For ΔABC, ∠A = 2x - 2, ∠B = 2x + 2, and ∠C = 5x. If ΔABC undergoes a dilation by a scale factor of 1 2 to create ΔA'B'C' with ∠A' = 58 - x, ∠B' = 3x - 18, and ∠C' = 120 - x, which confirms that ΔABC∼ΔA'B'C by the AA criterion?

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Mathematics

26 July, 13:49

For ΔABC, ∠A = 2x - 2, ∠B = 2x + 2, and ∠C = 5x. If ΔABC undergoes a dilation by a scale factor of 1 2 to create ΔA'B'C' with ∠A' = 58 - x, ∠B' = 3x - 18, and ∠C' = 120 - x, which confirms that ΔABC∼ΔA'B'C by the AA criterion?

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Brisa · Answer 1

The correct answer for the question that is being presented above is this one: "C) ∠B = ∠B' = 33° and ∠C = ∠C' = 80°."

A triangle has a total of 180 degrees. In order to get x:180 = 4x + 7 + 2x + 3 + 6x - 10180 = 12x - 0 x = 15

∠A = 4x + 7 = 67∠B = 2x + 3 = 33∠C = 6x - 10 = 80