Solve the equation 4c2 + 7c - 5 = 0 using the quadratic formfoula

Question

Nora Klein

Mathematics

10 June, 21:33

Solve the equation 4c2 + 7c - 5 = 0 using the quadratic formfoula

+2

Answers (1)

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Dork · Answer 1

Let's solve your equation step-by-step.

4c2+7c-5=0

Step 1: Use quadratic formula with a=4, b=7, c=-5.

c=

-b±√b2-4ac

2a

c=

- (7) ±√ (7) 2-4 (4) (-5)

2 (4)

c=

-7±√129

8

c=

-7

8

+

1

8

√129 or c=

-7

8

+

-1

8

√129

Answer:

c=

-7

8

+

1

8

√129 or c=

-7

8

+

-1

8

√129Let's solve your equation step-by-step.

4c2+7c-5=0

Step 1: Use quadratic formula with a=4, b=7, c=-5.

c=

-b±√b2-4ac

2a

c=

- (7) ±√ (7) 2-4 (4) (-5)

2 (4)

c=

-7±√129

8

c=

-7

8

+

1

8

√129 or c=

-7

8

+

-1

8

√129

Answer:

c=

-7

8

+

1

8

√129 or c=

-7

8

+

-1

8

√129Let's solve your equation step-by-step.

4c2+7c-5=0

Step 1: Use quadratic formula with a=4, b=7, c=-5.

c=

-b±√b2-4ac

2a

c=

- (7) ±√ (7) 2-4 (4) (-5)

2 (4)

c=

-7±√129

8

c=

-7

8

+

1

8

√129 or c=

-7

8

+

-1

8

√129

Answer:

c=

-7

8

+

1

8

√129 or c=

-7

8

+

-1

8

√129