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10 June, 21:33

Solve the equation 4c2 + 7c - 5 = 0 using the quadratic formfoula

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Answers (1)
  1. 10 June, 21:46
    0
    Let's solve your equation step-by-step.

    4c2+7c-5=0

    Step 1: Use quadratic formula with a=4, b=7, c=-5.

    c=

    -b±√b2-4ac

    2a

    c=

    - (7) ±√ (7) 2-4 (4) (-5)

    2 (4)

    c=

    -7±√129

    8

    c=

    -7

    8

    +

    1

    8

    √129 or c=

    -7

    8

    +

    -1

    8

    √129

    Answer:

    c=

    -7

    8

    +

    1

    8

    √129 or c=

    -7

    8

    +

    -1

    8

    √129Let's solve your equation step-by-step.

    4c2+7c-5=0

    Step 1: Use quadratic formula with a=4, b=7, c=-5.

    c=

    -b±√b2-4ac

    2a

    c=

    - (7) ±√ (7) 2-4 (4) (-5)

    2 (4)

    c=

    -7±√129

    8

    c=

    -7

    8

    +

    1

    8

    √129 or c=

    -7

    8

    +

    -1

    8

    √129

    Answer:

    c=

    -7

    8

    +

    1

    8

    √129 or c=

    -7

    8

    +

    -1

    8

    √129Let's solve your equation step-by-step.

    4c2+7c-5=0

    Step 1: Use quadratic formula with a=4, b=7, c=-5.

    c=

    -b±√b2-4ac

    2a

    c=

    - (7) ±√ (7) 2-4 (4) (-5)

    2 (4)

    c=

    -7±√129

    8

    c=

    -7

    8

    +

    1

    8

    √129 or c=

    -7

    8

    +

    -1

    8

    √129

    Answer:

    c=

    -7

    8

    +

    1

    8

    √129 or c=

    -7

    8

    +

    -1

    8

    √129
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