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13 January, 07:46

Mike and Joey bought identical loaves of bread and packages of bologna. Mike made sandwiches with 5 slices of bologna and had 4 slices of bread left when he ran out of meat. Joey made sandwiches with 4 slices of bologna and had 4 slices of meat when he ran out of bread. How many slices of bread were in each loaf?

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Answers (2)
  1. 13 January, 07:51
    0
    The correct answer is 28 slices of bread

    Step-by-step explanation:

    Let there be BO slices of bologna and BR slices of bread in a package.

    Mike use BO/5 (5 slides per sandwich) and he use bread, BR - 4 = BO/5 x2

    Joey use (BO-4) / 4 and BR = (BO-4) / 4 x2

    We know BO and BR are the same for each one, so we can replace BR in one equation and Isolate BO

    ((BO-4) / 4 x2) - 4 = BO/5 x2

    We divide each term by 2

    ((BO-4) / 4) - 2 = BO/5

    BO/4-1 - 2=BO/5

    BO/4-3=BO/5

    BO/4 - BO/5=3

    5BO-4BO/20=3

    1BO/20=3

    BO = 3x 20

    BO=60

    and BR = (BO-4) / 4 x2

    BR = (60-4) / 4 x2

    BR = (56) / 4 x2

    BR=14 x 2 = 28
  2. 13 January, 08:14
    0
    Mike had 14 slice of bread in his loaf while

    Joey had 8 slice of bread in his loaf.

    Step-by-step explanation:

    We should note that a sandwich is made up of two slice of bread.

    that is:

    A Sandwich = 2 Slice of bread

    and for bologna to be in a sandwich, you will have 2 slice of bread together.

    So, For Mike,

    2 slice of bread * 5 Sandwich = 10 Slice of bread

    Remaining Slice of bread = 4 Slice

    Total Slice of bread in Mike loaf = 10 + 4

    = 14 slice of bread was in Mike loaf of bread.

    For Joey

    A sandwich = 2 Slice of bread

    2 slice of bread * 4 Sandwich = 8 Slice of bread

    Remaining slice of bread = 0

    Total slice of bread in joey loaf = 8 slice of bread.
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