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2 March, 15:57

Suppose a normal distribution has a mean of 222 and a standard deviation of 16. What is the probability that a data value is between 174 and 238? Round your answer to the nearest tenth of a percent.

A. 66.9%

B. 53.3%

C. 84.0%

D. 91.0%

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  1. 2 March, 16:08
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    P (174 < x < 238) = P (x < 238) - P (x < 174) = P[z < (238 - 222) / 16] - P[z < (174 - 222) / 16] = P (z < 1) - P (z < - 3) = 0.84134 - 0.00135 = 0.83999 or 83.999%

    Answer: 84.0% to the nearest tenth.
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