23 August, 05:50
Which restriction is appropriate for the variable?
3y^2 - 3y/y-1
A. no restrictions are needed
B. y = - 1
C. y = 1
D. y = 3 <---
23 August, 06:33
Best answer is y=1
Because if the denominator is equals to 1, then the answer will be undefined and we don't want it to be undefined.
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» Which restriction is appropriate for the variable? 3y^2 - 3y/y-1 A. no restrictions are needed B. y = - 1 C. y = 1 D. y = 3 <---