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23 August, 05:50

Which restriction is appropriate for the variable?

3y^2 - 3y/y-1

A. no restrictions are needed

B. y = - 1

C. y = 1

D. y = 3 <---

+1
Answers (1)
  1. 23 August, 06:33
    0
    Best answer is y=1

    Because if the denominator is equals to 1, then the answer will be undefined and we don't want it to be undefined.
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