The population of a city 5 years ago was 36,000 people. By this year, the city's population had grown to 43,800 people. Assume the population has grown linearly and will continue to grow this way. What will the population of the city be 5 years from now? Assume the population has grown exponentially and will continue to grow this way. What will be the population of the city 5 years from now?

Question

Aden Sweeney

Mathematics

21 June, 02:15

The population of a city 5 years ago was 36,000 people. By this year, the city's population had grown to 43,800 people. Assume the population has grown linearly and will continue to grow this way. What will the population of the city be 5 years from now? Assume the population has grown exponentially and will continue to grow this way. What will be the population of the city 5 years from now?

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Answers (2)

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Ellis · Answer 1

Assuming linear growth means:

y=mx+b,

m = (y2-y1) / (x2-x1) = (43800-36000) / 5

m=1560

y=1560x+b, so y increases by 1560 for every year elapsed ...

43800+1560 (5) = 51600 people five years from now ...

Now for the exponential case:

43800/36000=ar^5/ar^0

73/60=r^5

r = (73/60) ^ (1/5)

43800 (73/60) ^ (1/5) ^ (5)

43800 (73/60)

53290 people five years from now ...

Enrique Summers · Answer 2

The population of the city 5 years from now would be 123,600