Find the domain and range for the absolute value function f (x) = | x+2 |-3

F (x) = |x + 2| - 3

0 = |x + 2| - 3

0 = x + 2 - 3

0 = x - 1

+ 1 + 1

1 = x

Domain: x > 1 and x < 1

Solution Set of the Domain: x and x or (1, 1)

f (x) = |x + 2| - 3

f (x) = |0 + 2| - 3

f (x) = |2| - 3

f (x) = 2 - 3

f (x) = - 1

Range: x ≤ 3

Solution Set of the Range: x or (-∞, 3]