Given the events below, determine which equation correctly calculates the probability of drawing two kings in a row from a standard 52-card deck, without replacement.

Event A: The first card drawn is a king.

Event B: The second card drawn is a king.

A. P (A n B) = P (A) * P (B|A)

B. P (A n B) = P (A) * P (B)

C. P (A n B) = P (A) * P (A|B)

D. P (A n B) = P (B) * P (B|A)

Question

Raegan Hurley

Mathematics

28 August, 21:10

Given the events below, determine which equation correctly calculates the probability of drawing two kings in a row from a standard 52-card deck, without replacement.

Event A: The first card drawn is a king.

Event B: The second card drawn is a king.

A. P (A n B) = P (A) * P (B|A)

B. P (A n B) = P (A) * P (B)

C. P (A n B) = P (A) * P (A|B)

D. P (A n B) = P (B) * P (B|A)

+3

Answers (1)

Know the Answer?

Jaelyn Dorsey · Answer 1

P of drawing two kings in a row = P of first card is a king * P of second card is a king given that the first card was a king

P (A ∩ B) = P (A) * P (B|A)

Answer: option A.

You can check that this is 4/52 * 3/51