Apples sell for $1.90 per pound, and bananas sell for $0.75 per pound. Troy bought some apples and some bananas. Together they weighed 3.8 pounds, and cost $5.84. Let p represent the number of pounds of apples Troy purchased. Which equation represents the problem described here?

A. 1.15p + 2.85 = 3.8

B. 1.9p + 0.75 = 3.8

C. 1.15p + 2.85 = 5.84

D. - 1.15p + 2.85 = 5.84

1.15p + 285 = 5.84

Step-by-step explanation:

This problem has two equations. Total cost and Total pounds. The cost and the pounds

p = apple pounds

b = banana pounds

Cost

1.90p +.75b = 5.84

Pounds

p + b = 3.8

Now we use the substitute method for system of equations to solve

p + b = 3.8

b = - p + 3.8

Now that we know what b equals, substitute is for b in the cost equation.

1.90p +.75b = 5.84

1.90p +.75 (-p+3.8) = 5.84

distribute / multiply. 75 by (-p+3.8)

1.90p + -.75p + 2.85 = 5.84

Combine the p values

1.15p + 285 = 5.84