Megan's mega buffet has a selection of 5 salads, 7 vegetables, 3 entrees, and 2 desserts. At lunch shyla plans to get 2 salads, two vegetables, 1 entree, and 1 dessert. How many different meals can she select

1260 is the answer

you can have 10 combination to choose 2 salads from 5 different salads

you can have 21 combination to choose 2 vegetables from 7 different vegetables

you can have 3 combination to choose 1 entree from 3 different entrees

you can have 2 combination to choose 1 dessert from 2 different dessert

Multiply those numbers together, 10X21X3X2

Therefore, answer is 1260 meals.

There is one hundred and seventy-five different meals she can make.