Solve 3x - 4 ≤ 2 or 2x + 11 ≥ - 1.

x

x

{all reals}

Question

Maren Graham

Mathematics

6 July, 18:52

Solve 3x - 4 ≤ 2 or 2x + 11 ≥ - 1.

x

x

{all reals}

+4

Answers (1)

Know the Answer?

Carlos Fleming · Answer 1

3x - 4 < = 2

3x < = 2 + 4

3x < = 6

x < = 6/3

x < = 2

2x + 11 > = - 1

2x > = - 1 - 11

2x > = - 12

x > = - 12/2

x > = - 6

however, since ur inequality has " or " instead of " and " ... ur answer I believe is going to be x < = 2

Solve 3x - 4 ≤ 2 or 2x + 11 ≥ - 1.xx{all reals}

Solve 3x - 4 ≤ 2 or 2x + 11 ≥ - 1.

x

x

{all reals}