Find the equation of the axis of symmetry and the coorinates of the vertex of the graph of the function y=4x^2+5x-1

a.) x=-5/8; vertex: (-5/8,-5 11/16)

b.) x=5/8; vertex: (5/8,3 11/16)

c.) x=5/8; vertex: (5/8, 4 5/8)

d.) x=-5/8; vertex: (-5/8,-2 9/16)

Question

23 August, 09:37

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Answers (1)

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Jett Friedman · Answer 1

The right answer is d) x = - 5/8; vertex: (-5,8, - 2 9/16)

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Find the equation of the axis of symmetry and the coorinates of the vertex of the graph of the function y=4x^2+5x-1a.) x=-5/8; vertex: (-5/8,-5 11/16)b.) x=5/8; vertex: (5/8,3 11/16)c.) x=5/8; vertex: (5/8, 4 5/8)d.) x=-5/8; vertex: (-5/8,-2 9/16)