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7 June, 07:52

A group of art students are painting a mural on a walls the rectangular wall has dimensions of (6x+7) by (8x+5) and they are planning the mural to be (x+4) by (2x+5). What is the area of the remaining wall after the mural has been painted

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Answers (2)
  1. 7 June, 07:55
    0
    46x^2 + 73x + 15

    Step-by-step explanation:

    Expand both equations

    Wall = (6x + 7) (8x + 5) = 48x^2 + 56x + 30x + 35 = 48x^2 + 86x + 35

    Mural = (x + 4) (2x + 5) = 2x^2 + 5x + 8x + 20 = 2x^2 + 13x + 20

    Minus them.

    Wall - Mural =

    (48x^2 + 86x + 35) - (2x^2 + 13x + 20)

    (48x^2 - 2x^2) + (86x - 13x) + (35 - 20)

    46x^2 + 73x + 15
  2. 7 June, 07:58
    0
    46x^2 + 73x + 15

    Step-by-step explanation:

    Expand both equations

    Wall = (6x + 7) (8x + 5) = 48x^2 + 56x + 30x + 35 = 48x^2 + 86x + 35

    Mural = (x + 4) (2x + 5) = 2x^2 + 5x + 8x + 20 = 2x^2 + 13x + 20

    Minus them.

    Wall - Mural =

    (48x^2 + 86x + 35) - (2x^2 + 13x + 20)

    (48x^2 - 2x^2) + (86x - 13x) + (35 - 20)

    46x^2 + 73x + 15
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