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18 March, 14:06

Let f (x) = x^2 - 2x + 2 and g (x) = x - 3. find f (x) times g (x)

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Answers (2)
  1. 18 March, 14:34
    0
    g (x) ^2=x^2-6x+9=f (x) - 4x+7, f (x) = g (x) ^2-4g (x) - 5 = (g (x) - 2) ^2-9 = (g (x) + 7) * (g (x) - 11)

    f (x) = x^2-2x+2=g (*) ^2+4x-7
  2. 18 March, 14:35
    0
    x³ - 5x² + 8x - 6

    Step-by-step explanation:

    (x² - 2x + 2) (x - 3) ← product is required

    Each term in the second factor is multiplied by each term in the first factor, that is

    x² (x - 3) - 2x (x - 3) + 2 (x - 3) ← distribute all 3 parenthesis

    = x³ - 3x² - 2x² + 6x + 2x - 6 ← collect like terms

    = x³ - 5x² + 8x - 6 → (b)
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