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Dustin Chan
Mathematics
2 August, 03:09
If sec0+tan0=p, then find the value of cosec0.
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Fisher Blake
2 August, 03:25
0
Step-by-step explanation:
p=sec0+tan0
=1/cos0 + sin0/cos0
= (1+sin0) / cos0
square both sides
(1+sin) ^2 / cos^2 = p^2
(1+sin) ^2 / (1 - sin^2) = p^2
(1+sin) ^2 / ((1-sin) (1+sin)) = p^2
(1+sin) / (1-sin) = p^2
1+sin=p^2-p^sin
sin+p^2sin=p^2-1
sin (1+p^2) = (p^2-1)
sin = (1-p^2) / (1+p^2)
cosec=1/sin
= (1+p^2) / (1-p^2)
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