Kaylib's eye-level height is 48 ft above sea level, and Addison's eye-level height is 85 1/3 ft above sea level. How much farther can Addison see to the horizon? Use the formula d=sq-rt (3h) / (2), with d being the distance they can see in miles and h being their eye-level height in feet.

a. sq-r 2 mi

b. 2 sq-r 2 mi

c. 14 sq-r

d 28sq-r2

Question

Valencia

Mathematics

27 November, 23:31

Kaylib's eye-level height is 48 ft above sea level, and Addison's eye-level height is 85 1/3 ft above sea level. How much farther can Addison see to the horizon? Use the formula d=sq-rt (3h) / (2), with d being the distance they can see in miles and h being their eye-level height in feet.

a. sq-r 2 mi

b. 2 sq-r 2 mi

c. 14 sq-r

d 28sq-r2

+3

Answers (1)

Know the Answer?

Nadia · Answer 1

The distance they can see: d = √ (3 h / 2)

d (Addison) = √ (3 · 256/3 / 2) = √ 124 = √ 64 · 2 = 8 √ 2d (Kaylib) = √ (3 · 48 / 2) = √ 72 = √ 36 · 2 = 6 √ 2d (Addison) - d (Kaylib) = 8 √ 2 - 6 √ 2 = 2 √ 2Answer: b. 2 √ 2 mi.