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10 January, 20:56

A sequence is defined recursively by: f (1) = 4; f (n) = f (n-1) + 3n. Find f (5).

[1] 16 [2] 24 [3] 33 [4] 46

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  1. 10 January, 21:12
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    If you would like to find f (5), you can calculate this using the following steps:

    f (1) = 4

    f (n) = f (n-1) + 3 * n

    f (2) = f (2-1) + 3 * 2 = f (1) + 6 = 4 + 6 = 10

    f (3) = f (3-1) + 3 * 3 = f (2) + 9 = 10 + 9 = 19

    f (4) = f (4-1) + 3 * 4 = f (3) + 12 = 19 + 12 = 31

    f (5) = f (5-1) + 3 * 5 = f (4) + 15 = 31 + 15 = 46

    The correct result would be [4] 46.
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