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25 July, 03:21

Find the solution to the system of equations, x+3y and 2x+4y=8

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  1. 25 July, 03:28
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    x = - 7/3y + 8/3

    y = - 3/7x + 8/7

    Step-by-step explanation:

    First, set the equations next to each other to find x and y, I'll start with x:

    x + 3y + 2x + 4y = 8

    Combine like terms

    3x + 7y = 8

    Subtract both sides by 7y

    3x + 7y - 7y = 8 - 7y

    3x = 8 - 7y

    I'll re-order the equation to make it easier to divide

    3x = - 7y + 8

    Divide both sides by 3

    3x / 3 = - 7y + 8 / 3

    x = - 7/3y + 8/3

    If you need decimals just divide with a calculator

    Now to find y:

    We already combined like terms so we don't need to do that again ...

    3x + 7y = 8

    Subtract both sides by 3x

    3x - 3x + 7y = 8 - 3x

    7y = 8 - 3x

    I'll reorder the equation once again so the variable comes first

    7y = - 3x + 8

    Divide both sides by 7

    7y / 7 = - 3x + 8 / 7

    y = - 3/7x + 8/7

    Again, use a calculator to divide completely for decimals.
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