Mathematics

5 April, 13:31

M∠ABDm, angle, A, B, D is a straight angle.

/qquad m / angle ABC = 8x - 41^/circm∠ABC=8x-41

∘

m, angle, A, B, C, equals, 8, x, minus, 41, degrees

/qquad m / angle CBD = 9x + 17^/circm∠CBD=9x+17

∘

m, angle, C, B, D, equals, 9, x, plus, 17, degrees

Find m/angle CBDm∠CBDm, angle, C, B, D:

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