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26 June, 06:48

What are the solutions of the equation: z^2 - 12z + 36 = 0?

A. - 6, 6

B. 6, 6

C. 6, - 6

D. - 6, - 6

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Answers (1)
  1. 26 June, 07:00
    0
    Factor by groups

    (Z^2 - 6z) (-6z+36)

    GCF 1st binomial is z

    GCF of 2nd binomial is - 6

    (z-6) (z-6)

    Solutions

    6,6
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