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Mcgee
Mathematics
2 July, 05:52
Y=x^2+12x+30 8x-y=10
+5
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Stephany Mcneil
2 July, 05:56
0
Y=x^2+12x+30
8x-y=10
sub x^2+12x+30 for y in the secodn equaiton
8x - (x^2+12x+30) = 10
8x-x^2-12x-30=10
-x^2-4x-30=10
times - 1
x^2+4x+30=-10
add 10 both sides
x^2+4x+40=0
use quadratic formula
we find that we have 2 imaginary roots and therefor are not on the real plane, they are not plotted on the imaginary plane
no real solution
x=-2+6i or - 2-6i
the interseciton on the imaginary plane is
(-2+6i, - 26+48i) or (-2-6i,-26-48i)
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Danielle Mcintyre
2 July, 06:03
0
Y = x² + 12x + 30
8x - y = 10
8x - y = 10
- 8x - 8x
-y = - 8x + 10
-1 - 1
y = 8x - 10
x² + 12x + 30 = 8x - 10
- 8x - 8x
x² + 4x + 30 = - 10
- 10 - 10
x² + 4x + 20 = 0
x = - b ± √b² - 4ac
2a
x = - 4 ± √4² - 4 (1) (20)
2 (1)
x = - 4 ± √16 - 4 (20)
2
x = - 4 ± √16 - 80
2
x = - 4 ± √-64
2
x = - 4 ± 8i
2
x = - 2 ± 4i
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