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29 November, 10:54

The lateral area of a frustum of a regular triangular pyramid is 1,081cm^2, and the altitude and lateral edges are 24cm and 26cm, respectively. Find the lengths of the sides of the bases.

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  1. 29 November, 11:10
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    Lateral Area = 3 * (a + b) / 2 * 24

    1,081 = 36 * (a + b) / : 36

    a + b ≈ 30

    ((a - b) / 2) ² = 26 ² - 24² = 676 - 576 = 100

    (a - b) / 2 = 10

    a - b = 20

    a = b + 20

    a + b = 30

    2 b + 20 = 30

    2 b = 10

    b = 10 : 2

    b = 5 cm

    a = 5 + 20

    a = 25 cm
  2. 29 November, 11:16
    0
    Thats hard very hard is that your homework wow long and very hard
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