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Braiden Shea
Mathematics
4 June, 21:51
Solve by substitution 3x+y=5 and 2x-y=10
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Killian Marshall
4 June, 22:12
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3x+5=2x-10
-2x - 2x
X+5=-10
-5 - 5
X=-15
3 (-15) + y=5
-45+y=5
+45 + 45
y=50
2 (-15) - y=10
-30-y=10
+30 + 30
-y=40
Divide by - 1 on both sides
y=-40
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