Factor 9x6 - 16 y completely.

First factor each term.

9x6 = (__) ?

16y6 = () 2

Then use a? - b2 = (a - b) (a + b). Show your work.

9x6 - 16y6 =

Question

Rubi Mclaughlin

Mathematics

10 September, 17:10

Factor 9x6 - 16 y completely.

First factor each term.

9x6 = (__) ?

16y6 = () 2

Then use a? - b2 = (a - b) (a + b). Show your work.

9x6 - 16y6 =

+4

Answers (1)

Know the Answer?

Natalya Huff · Answer 1

(3x^3 - 4y^3) (3x^3 + 4y^3)

Step-by-step explanation:

9x^6 - 16 y^6

Rewriting as

(3x^3) ^2 - (4y^3) ^2

This is the difference of squares a^2 - b^2 = (a-b) (a+b)

(3x^3 - 4y^3) (3x^3 + 4y^3)

Factor 9x6 - 16 y completely.First factor each term.9x6 = (__) ?16y6 = () 2Then use a? - b2 = (a - b) (a + b). Show your work.9x6 - 16y6 =

Factor 9x6 - 16 y completely.

First factor each term.

9x6 = (__) ?

16y6 = () 2

Then use a? - b2 = (a - b) (a + b). Show your work.

9x6 - 16y6 =