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Athena Middleton
Mathematics
9 August, 23:25
Solve y-2x=3 and 3x-2y=5 using substitution
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Serenity Carlson
9 August, 23:35
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Y - 2x = 3
3x - 2y = 5
y - 2x = 3
Add 2x to both sides:
y = 2x + 3
Plug in 2x + 3 for 'y' in the 2nd equation:
3x - 2 (2x + 3) = 5
Distribute - 2:
3x - 4x - 6 = 5
Combine like terms:
-x - 6 = 5
Add 6 to both sides:
-x = 11
Multiply - 1 to both sides:
x = - 11
Now plug this into any of the 2 equations to solve for 'y':
y - 2x = 3
y - 2 (-11) = 3
Multiply:
y + 22 = 3
Subtract 22 to both sides:
y = - 19
So the solution is (-11, - 19)
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