After a new $28,000 car is driven off the lot, it begins to depreciate at a rate of 18.9% annually.

Which function describes the value of the car after t years?

1) C (t) = 28,000 (0.158) ^t

2) C (t) = 28,000 (0.811) ^t

3) C (t) = 28.000 (1.575) ^t

4) C (t) = 28.000 (0.189) ^t

Question

Natalia Wood

Mathematics

6 May, 14:34

After a new $28,000 car is driven off the lot, it begins to depreciate at a rate of 18.9% annually.

Which function describes the value of the car after t years?

1) C (t) = 28,000 (0.158) ^t

2) C (t) = 28,000 (0.811) ^t

3) C (t) = 28.000 (1.575) ^t

4) C (t) = 28.000 (0.189) ^t

+3

Answers (1)

Know the Answer?

Imani Owens · Answer 1

2

Step-by-step explanation:

We get 0.811 as our depreciating value because we take 18.9% and turn it into a decimal. Then, we subtract that from 1. If we did 0.189 instead, it would depreciate at a rate of 81.1% annually.

After a new $28,000 car is driven off the lot, it begins to depreciate at a rate of 18.9% annually.Which function describes the value of the car after t years?1) C (t) = 28,000 (0.158) ^t2) C (t) = 28,000 (0.811) ^t3) C (t) = 28.000 (1.575) ^t4) C (t) = 28.000 (0.189) ^t

After a new $28,000 car is driven off the lot, it begins to depreciate at a rate of 18.9% annually.

Which function describes the value of the car after t years?

1) C (t) = 28,000 (0.158) ^t

2) C (t) = 28,000 (0.811) ^t

3) C (t) = 28.000 (1.575) ^t

4) C (t) = 28.000 (0.189) ^t