Write he equation that is perpendicular to the graph of 8x+4y=3 and intersects that graph at its x-intercept.

8x + 4y = 3 ... to find x int, sub in 0 for y and solve for x

8x + 4 (0) = 3

8x = 3

x = 3/8 ... so the x int is (3/8,0)

8x + 4y = 3

4y = - 8x + 3

y = - 2x + 3/4 ... slope here is - 2. A perpendicular line will have a negative reciprocal slope. So the slope we need for our perpendicular line is 1/2.

y = mx + b

slope (m) = 1/2

(3/8,0) ... x = 3/8 and y = 0

now we sub and find b, the y int

0 = 1/2 (3/8) + b

0 = 3/16 + b

-3/16 = b

so ur perpendicular line going thru the x int is : y = 1/2x - 3/16