Evaluate the summation of 3 times negative 2 to the n minus 1 power, from n equals 1 to 5.

Choices:

A.-93

B.-33

C. 33

D. 93

The answer is C. 33

3 * (-2) ⁿ⁻¹

n = 1; 3 * (-2) ¹⁻¹ = 3 * (-2) ⁰ = 3 * 1 = 3

n = 2; 3 * (-2) ²⁻¹ = 3 * (-2) ¹ = 3 * (-2) = - 6

n = 3; 3 * (-2) ³⁻¹ = 3 * (-2) ² = 3 * 4 = 12

n = 4; 3 * (-2) ⁴⁻¹ = 3 * (-2) ³ = 3 * (-8) = - 24

n = 5; 3 * (-2) ⁵⁻¹ = 3 * (-2) ⁴ = 3 * 16 = 48

The sum is:

3 + (-6) + 12 + (-24) + 48 = 3 - 6 + 12 - 24 + 48 = 33