Suppose a parabola has a vertex in quadrant IV and a<0 in the equation y=ax^2+bx+c. how many real solutions will the equation ax^2+bx+c=0 have?

Question

Brooks Case

Mathematics

10 March, 18:40

Suppose a parabola has a vertex in quadrant IV and a<0 in the equation y=ax^2+bx+c. how many real solutions will the equation ax^2+bx+c=0 have?

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Answers (1)

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Milo Shaffer · Answer 1

Given the vertex is in quadrat IV, it is below the y-axis.

Given a < 0, the parabola open downdards.

Those two facts together implies that the parabola does not touch the y-axis, meaning y is never 0, and the equation ax^2 + bx + c = 0 does not have any real solutions.

Answer; None