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Alessandro Stephens
Mathematics
22 September, 11:03
Multiply k+3/4k-2 * (12k^2 - 3)
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Gilbert
22 September, 11:05
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k+3/4k-2 * (12k^2 - 3) would become k+3/2 (2k-1) * 3 (2k+1) (2k-1).
Cross out the (2k-1) 's. Then we get k+3/2*6k+3 Now we just multiply
We then get, (6k^2+21k+9) / 2
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