A manufacturer wants to double the volume of a 3 in.2 in.6 in. 3 i n. * 2 i n. * 6 i n. box, while using as little extra cardboard as possible. Which statement is true?

Question

Jamiya Roman

Mathematics

15 January, 16:23

A manufacturer wants to double the volume of a 3 in.2 in.6 in. 3 i n. * 2 i n. * 6 i n. box, while using as little extra cardboard as possible. Which statement is true?

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Answers (1)

Know the Answer?

Lila Hinton · Answer 1

Answer: 2 inch dimension will give smallest increase.

Step-by-step explanation:

Length = 3 in

width = 2 in

height = 6 in

Extra cardboard means to find surface area

on doubling the length

length = 6 In

width = 2 In

Height = 6In

Surface area for the above dimensions = 2 [ 6x2+2x6+6x6] = 120 sq in

On doubling the width

length = 3 in

width = 4 in

Height = 6 inch

Surface area for the above dimensions = 2 [ 3x4+4x6+6x3] = 2[54] = 108 sq inches

On doubling height

Length = 3 in

width = 2 in

Height = 12 in

Surface area for above dimensions = 2 [ 3x2+2x12+12x3] = 2[6+24+36] = 132 sq inch

On doubling width surface area is minimum.

A manufacturer wants to double the volume of a 3 in.*2 in.*6 in. 3 i n. * 2 i n. * 6 i n. box, while using as little extra cardboard as possible. Which statement is true?

A manufacturer wants to double the volume of a 3 in.2 in.6 in. 3 i n. * 2 i n. * 6 i n. box, while using as little extra cardboard as possible. Which statement is true?