Cade throws a baseball from a starting height of 6 feet, with an initial velocity of 22 feet per second. Which of the following equations shows the path of the baseball?

H (t) = - 16t^2 + 6t + 22

H (t) = - 16t^2 + 22t + 6

H (t) = - 16t^2 + 28t

H (t) = - 16t^2 + 28

Question

Camron Moreno

Mathematics

25 October, 11:33

Cade throws a baseball from a starting height of 6 feet, with an initial velocity of 22 feet per second. Which of the following equations shows the path of the baseball?

H (t) = - 16t^2 + 6t + 22

H (t) = - 16t^2 + 22t + 6

H (t) = - 16t^2 + 28t

H (t) = - 16t^2 + 28

+1

Answers (1)

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Joselyn Hickman · Answer 1

The correct answer for the question that is being presented above is this one: "H (t) = - 16t^2 + 22t + 6." Cade throws a baseball from a starting height of 6 feet, with an initial velocity of 22 feet per second. The equation that shows the path of the baseball is this H (t) = - 16t^2 + 22t + 6

Cade throws a baseball from a starting height of 6 feet, with an initial velocity of 22 feet per second. Which of the following equations shows the path of the baseball?H (t) = - 16t^2 + 6t + 22H (t) = - 16t^2 + 22t + 6H (t) = - 16t^2 + 28tH (t) = - 16t^2 + 28

Cade throws a baseball from a starting height of 6 feet, with an initial velocity of 22 feet per second. Which of the following equations shows the path of the baseball?

H (t) = - 16t^2 + 6t + 22

H (t) = - 16t^2 + 22t + 6

H (t) = - 16t^2 + 28t

H (t) = - 16t^2 + 28