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22 January, 14:33

What are the zeroes of f (x) = y2 - 2x - 3?

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Answers (2)
  1. 22 January, 14:48
    0
    x=y^2/2 - 3/2
  2. 22 January, 15:02
    0
    Step-by-step explanation:

    Product = - 3

    Sum = - 2

    Factors = - 3, 1

    y² - 2y - 3 = y² + y - 3y - 3

    = y (y + 1) - 3 (y + 1)

    = (y + 1) (y - 3)
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