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16 February, 09:35

The difference of the square of a number and 28 is equal to three times the number find the negative solution

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  1. 16 February, 09:59
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    Answer:y=-4

    Step-by-step explanation:

    To find this

    We get,

    The difference between the square of the number

    Let y be the unknown number

    Square of y=y^2

    Y^2-28=3y

    Then let we are going to rearrange, then we get

    y^2-3y-28

    We are going to factorise

    y^2-7y+4y-28

    (y^2-7y + (4y-28)

    y (y-7) + 4 (y-7) = 0

    (y+4) (y-7) = 0

    To find the negative number then we have

    y=-4
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